SOLUTION: log(2+x)-log(x-2)=log5

Question 1128269: log(2+x)-log(x-2)=log5
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39621)   (Show Source): You can put this solution on YOUR website!
What is the base? 2, 10, 5, what? Something else?

OKay need not be given the base.
--------note: this very first line is a mistake,

therefore all of this is still wrong:
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arguments must be equal.

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The original equation shows MINUS of a log; not the PLUS of a log.
First two steps should have been:

.
.
Answer by ikleyn(52817)   (Show Source): You can put this solution on YOUR website!
.
log(2+x)-log(x-2)=log5
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            The solution by @josgarithmetic is INCORRECT.

            Below find the correct solution.

log(2+x) - log(x-2) = log(5) ====> = 5 ====> 2 + x = 5*(x - 2) 2 + x = 5x - 10 2 + 10 = 5x - x 12 = 4x x = = 3. ANSWER

Again, although @josgaritmetic eventually got the correct answer, his solution is WRONG.

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