SOLUTION: log(x^3-1)=log(x^2+x+1)

Algebra.Com
Question 1128151: log(x^3-1)=log(x^2+x+1)
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
log(x^3-1)=log(x^2+x+1)
--------------
Since the logs are equal:
x^3-1 = x^2+x+1

------

x = 2, the only real root

RELATED QUESTIONS

Log(x+2) - log(x-1) = logx -... (answered by ewatrrr)
log(x-3)+log(2)=1 (answered by fractalier)
1/2 log... (answered by edjones)
log(log x) =... (answered by stanbon)
log(log x) =... (answered by nerdybill)
How do I work log(x-1)-log(x+6)=log(x-2)-log(x+3) (answered by josgarithmetic)
log(x-1)+log(x+1)=2 (answered by vleith)
log(x+1)+log(x-2)=1 (answered by Alan3354,josmiceli)
Log 3... (answered by ewatrrr)