SOLUTION: solve the simultaneous equation: 1.) log2^x - log2^y =2, log2^(x-2y) =3

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Question 1123813: solve the simultaneous equation:
1.) log2^x - log2^y =2, log2^(x-2y) =3
Found 2 solutions by Alex.33, MathTherapy:
Answer by Alex.33(110)   (Show Source): You can put this solution on YOUR website!
Assume that 2 s are the bases of the log, not contained in the expressions.
(If not please resubmit the qustion with the base specified, in case a bare log x can be recognized to be base e or 10)






Hope this solves your problem. Thanks!
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

solve the simultaneous equation:
1.) log2^x - log2^y =2, log2^(x-2y) = 3 
If it's , then . 

If not, you're on your own! 

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