SOLUTION: given that log8^(p+2) +log8^q=r-1/3and log2^(p-2)-log2^q=2r+1 then show that pē=4+32^r
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Question 1122163: given that log8^(p+2) +log8^q=r-1/3and log2^(p-2)-log2^q=2r+1 then show that pē=4+32^r
Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!
The "^" symbol is used to represent exponents -- not to indicate the base of a logarithm. Your question is
Given that and then show that
It looks ugly (especially the way you showed it!), but everything falls in place nicely using basic rules of logarithms. Specifically, we need to use
log(a)+log(b) = log(ab)
log(a)-log(b) = log(a/b)
log base 2 of x = 3*log base 8 of x, since 8 = 2^3
(1) Given
(2) Given
(3) from (1)
(4) from (3)
(5) from (2)
(6) from (4) and (5)
(7) (definition of log base 2)
(8)
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