SOLUTION: Complete the table assuming continuously compounded interest. (Round your answers to two decimal places.) Initial Investment: $900 Annual % Rate: UNKNOWN Time to Double (Year

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Question 1119112: Complete the table assuming continuously compounded interest. (Round your answers to two decimal places.)
Initial Investment: $900
Annual % Rate: UNKNOWN
Time to Double (Years): UNKNOWN
Amount after 10 Years: $1305

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39625)   (Show Source): You can put this solution on YOUR website!
Initial Investment: $900
Annual % Rate: 3.716%
Time to Double (Years): 18.65 years
Amount after 10 Years: $1305



If using a model , then value for the constant in the exponent is .

Answer by ikleyn(52848)   (Show Source): You can put this solution on YOUR website!
.
The model is  


y = 900*e^(k*t).


You are given that y = 1305 at t =10.  Write it as an equation:


1305 = 900*e^(k*10).


It is equivalent to  (after dividing both sides by 900):


 = ,   or    = 1.45.


Take the natural logarithm of both sides:


k*10 = ln(1.45)  ====>  10k = 0.37156  ====>  k =  = 0.037156.


Thus the model is  y = .


Time to double:


1800 =   ====>  


2 = .


Take the natural logarithm of both sides:


ln(2) = 0.037156*t  ====>  t =  =  = 18.65 years.


Answer. Annual rate is   = 1.038.

        Equivalent annual percentage rate is 3.8% (considered as annually compounded)

        Time to double is 18.65 years.


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