SOLUTION: Rewrite as a single logarithm:
2logx - 1/2log(x^2+1) + 2log(x-3)
Thank you!
Algebra.Com
Question 111676: Rewrite as a single logarithm:
2logx - 1/2log(x^2+1) + 2log(x-3)
Thank you!
Answer by malakumar_kos@yahoo.com(315) (Show Source): You can put this solution on YOUR website!
2logx - 1/2log(x^2+1) + 2log(x-3)
2logx+2log(x-3) - 1/2log(x^2+1)
logx^2+log(x-3)^2 - 1/2log(x^2+1)
log(x^2.(x-3)^2) - log(x^2+1)^1/2
log[x^2.(x-3)^2/(x^2+1)^1/2].
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