SOLUTION: How do you solve?
11 - 5log3 (x - 5) = 6
log x = 1 - log(x + 3)
and
e^6^y = 25
Thanks in advanced.
Algebra.Com
Question 111488: How do you solve?
11 - 5log3 (x - 5) = 6
log x = 1 - log(x + 3)
and
e^6^y = 25
Thanks in advanced.
Answer by wgunther(43) (Show Source): You can put this solution on YOUR website!
first one,
At this point you can take both sides to be exponents of 3
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second one
take both sides to be an exponent of 10
Just check for extranous values, because there is only one solution to the problem but the quadratic will give you two.
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third one. Here, it would have been helpful if you had been more clear. is it or . This is not communitive, meaning these mean different things. I'm going to assume you meant the second one because that is the literal translation of what you said.
Take natural log of both sides
Take log base 6 of both sides
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