SOLUTION: Log(36/25)^3+3log2/9-log2=2log16/125 -proof

Question 1114689: Log(36/25)^3+3log2/9-log2=2log16/125 -proof
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Straightforward application of the rules of logarithms....
(1) log(a)+log(b) = log(ab)
(2) log(a)-log(b) = log(a/b)
(3) log(a^b) = b*log(a)

And you didn't show the equation correctly; more parentheses are needed. It should be

log((36/25)^3) + 3log(2/9) - log(2) = 2log(16/125)

You can do the work.

RELATED QUESTIONS
Solution of... (answered by Fombitz)

3log2 64+e^ln5+log1/3... (answered by drk)

how to solve the sum x-log 48+3log2=1by3log 125-log3 (answered by Alan3354)

Solve fora in log(2a)- 3log2=... (answered by MathLover1,lwsshak3)

3log2/5-log72/125+log9 (answered by ewatrrr)

help me please... (answered by Alan3354)

1. log5 X = 3 2. log 25 125 (answered by mathispowerful)

log x = log6 36 + log81 9 � log2 4 (answered by nerdybill)

log sqrt x = log1 -... (answered by jsmallt9)