SOLUTION: Without using a graphing calculator, how do you graph logy-log((x-3))=log((x+3))

Question 1114646: Without using a graphing calculator, how do you graph logy-log((x-3))=log((x+3))
Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
logy-log((x-3))=log((x+3))
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log[y/(x-3)] = log(x+3)
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y/(x-3) = (x+3)
y = x^2+9
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Cheers,
Stan H.

Answer by ikleyn(52798) (Show Source): You can put this solution on YOUR website!
.

log(y) - log(x-3) = log(x+3) ====> the domain of this equation is x > 3 log(y) = log(x+3) + log(x-3) log(y) = log((x+3)*(x-3)) ====> y = (x+3)*(x-3) in the domain x > 3. y = x^2 - 9 in the domain x > 3 So the plot is the branch of the parabola y = x^2 - 9 over the domain x > 3.

The other's tutor solution is INCORRECT.

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