SOLUTION: Find the equation of the line passing through the point (2, 1) and perpendicular to the line 2y = 7 � x

Question 1113244: Find the equation of the line passing through the point (2, 1) and
perpendicular to the line 2y = 7 � x
Found 2 solutions by solver91311, Alan3354:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Put the given equation into Slope-Intercept Form, namely

Divide by 2 and rearrange the RHS:

Now the coefficient on represents the slope of the straight-line graph of the equation.

The slopes of perpendicular lines are negative reciprocals of each other, so, since the slope of the given line is , the slope of the desired line must be 2.

To derive an equation of a line given a slope and a point, use the Point-Slope form:

where is the given point and is the given slope. For and :

This is one possible equation that represents the desired line, however, note that it is impossible to find the equation of a line because for any given line the set of equations representing that line is uncountably infinite. Since you don't specify a form, I'll let you manipulate the answer to satisfy the requirements of your Algebra course.

.

John

My calculator said it, I believe it, that settles it

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the equation of the line passing through the point (2, 1) and
perpendicular to the line 2y = 7 � x
---------------
Find the slope of 2y = 7 � x
The slope of lines perpendicular, m, is the negative inverse of the slope of 2y = 7 � x
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Use y-y1 = m*(x-x1) where (x1,y1) is the point.

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