SOLUTION: With log 2 = .301 and log 3=.477. How am I suppose to find log .006 with those?

Question 1109946: With log 2 = .301 and log 3=.477. How am I suppose to find log .006 with those?
Answer by ikleyn(52814) (Show Source): You can put this solution on YOUR website!
.

0.006 = .


Therefore,  log(0.006) = log(2) + log(3) - log(1000) = log(2) + log(3) - 3 

                       = substitute the given values for log(2)  and  log(3)  and calculate.

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