SOLUTION: find the numerical value of the log expression.
log a = 9 log b = -7 log c = 4
log(c^(6))/(a^(6)b^(4))
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Question 1108884: find the numerical value of the log expression.
log a = 9 log b = -7 log c = 4
log(c^(6))/(a^(6)b^(4))
if you cant read the question, here's a screenshot.
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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the numerical value of the log expression.
log a = 9 log b = -7 log c = 4
log(c^(6))/(a^(6)b^(4)) = log(c^6)-[log(a^6)+log(b^4)
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= 6log(c) - [6log(a)+4log(b)]
======
= 6(4) - [6(9) + 4(-7)]
======
= 24 -[54-28]
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= 24 - 26
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= -2
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Cheers,
Stan H.
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