SOLUTION: find the numerical value of the log expression.
log a = 9 log b = -7 log c = 4
log(c^(6))/(a^(6)b^(4))
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Question 1108882: find the numerical value of the log expression.
log a = 9 log b = -7 log c = 4
log(c^(6))/(a^(6)b^(4))
if you cant read the question, here's a screenshot.
http://prntscr.com/ibpg0m
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Found 2 solutions by stanbon, josgarithmetic:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
answered
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
log(c^(6))/(a^(6)b^(4))
log(((c^(6))/(a^(6)b^(4))))
You can now do the substitutions and finish the rest.
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