SOLUTION: I still didn't get an answer for this one. It's not a typo, as far as I know, but I can't get started on it. Solve the following exponential equation: 49 over(/) 1-1e^3x = 6

Question 110850: I still didn't get an answer for this one. It's not a typo, as far as I know, but I can't get started on it.
Solve the following exponential equation:
49 over(/) 1-1e^3x = 68
If there's a typo, it could be 1-1e^3x is supposed to be read 1-1e_3x, but the 3x definitely looks like a little exponent and not a base.
Found 2 solutions by scott8148, MathLover1:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
multiplying by (1-1e^3x) and dividing by 68 gives 49/68=1-1e^3x

subtracting 1 and multiplying by -1 gives 19/68=e^3x

taking the natural log gives ln(19/68)=3x
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
�..multiply both sides by

..........divide both sides by
.........
..........
..........move to the left and to the right
..........

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