SOLUTION: Rewrite each expression as a single logarithm: a) log 2 + log x � (log 3 + log y) b) log 5 � log 7 c) (log 24 + log 12) � log 6 I�m so confused what this question is asking a

Question 1107098: Rewrite each expression as a single logarithm:
a) log 2 + log x � (log 3 + log y)
b) log 5 � log 7
c) (log 24 + log 12) � log 6
I�m so confused what this question is asking and I don�t know what to do.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Rewrite each expression as a single logarithm:
a) log 2 + log x � (log 3 + log y)
----
Adding logs --> multiply
Subtracting logs --> divide
================
Use parentheses
---
log(2) + log(x) � (log(3) + log(y))
= log(2x) � (log(3y)
= log(2x/3y)
==================
Do the others the same way.
RELATED QUESTIONS
Write as a single logarithm a) 2 log 5 log b b) 3 log x + 1/2 log y c) 2 log m + log n (answered by lwsshak3)

Log a-2 log b +3 log c (Rewrite the expression as a single... (answered by lwsshak3)

Write�this�expression�in�a�single�logarithm�log�2�+�log�5: a. log�2.5 b. log�10 c.... (answered by MathLover1)

Rewrite the expression as a single logarithm. 1/2 [log(x) + log(y)] -... (answered by ikleyn)

How do i write these as a single logarithm? 1) (log 3 - log 4) - log 2 2) log 2 +... (answered by Boreal)

Write each logarithmic expression as a single logarithm. 24. log 2 + 3 log 1 2... (answered by Alan3354)

Write as single logarithm a) log(x) + log(y) -log(z) b) log(m) -(log(n) + log(p)) c)... (answered by Alan3354)

find the following expression as a single logarithm: log x + log 7 - log y (answered by Alan3354)

Write as a single logarithm: 2 log A-3 log B+4 log... (answered by Alan3354)