SOLUTION: 3^(2x)-3^(2x-1)=18 Solving with logarithms. Exponents in paratheses Thank you

SOLUTION: 3^(2x)-3^(2x-1)=18 Solving with logarithms. Exponents in paratheses Thank you

Algebra.Com

Question 1106528: 3^(2x)-3^(2x-1)=18 Solving with logarithms. Exponents in paratheses Thank you
Answer by ikleyn(52914) (Show Source): You can put this solution on YOUR website!
.

 = 18 


    is the same as


 = 18


    is the same as


 = 18 


    is equivalent to


 =  = 27 = 


    implies


2x = 3,  i.e.  x = 1.5.

RELATED QUESTIONS
Need help please with solving equations involving rational exponents. Solve equation.... (answered by sudhanshu_kmr)

Please solve: 8^(x+1) = 3^2x note that (x+1) and 2x are exponents Thank... (answered by josmiceli)

(x+3)(2x+1)(2x) Thank... (answered by richwmiller)

Hi, can you help me by solving the equation: 5[2x-5]+3=18 (The ''['' are absolute value) (answered by stanbon)

I need help solving each system. Thank you. x-2y-z=3 2x+y-2z=1... (answered by lwsshak3)

Can you please help me. It is solving linear equations with fraction. 3/2x + 1/5= 3/4... (answered by macston)

Need help solving this equation with rational exponents please. Solve equation. Check... (answered by jsmallt9)

logarithms, log2(x+3)-log2(2x-1)=2 my problem is with the subtraction... (answered by Alan3354)

use the properties of logarithms to write the single logarithm as a sum and/or difference (answered by jsmallt9)