SOLUTION: I have this problem: 4log(base6)x=log(base6)64. My answer was x=64^1/4. I was hesitant to go with this answer because my textbook had no examples that ended in an answer like that.

Question 1102961: I have this problem: 4log(base6)x=log(base6)64. My answer was x=64^1/4. I was hesitant to go with this answer because my textbook had no examples that ended in an answer like that. Is this correct? If not, how do I solve this correctly? Thanks!1/4
Answer by greenestamps(13216) (Show Source): You can put this solution on YOUR website!

Solving the equation is rather easy, since we have log base 6 on both sides.

We get , so your answer is valid.

However, it can be simplified in many ways, without resorting to an irrational approximation obtained with a calculator.

All of those forms are equivalent. In most situations either or would be considered the best forms.
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