SOLUTION: log3 (x-4y+5)=0 and log3 (x-1)-log3 y=1 simaltenously

Algebra.Com
Question 1102526: log3 (x-4y+5)=0 and log3 (x-1)-log3 y=1
simaltenously

Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!

Learn how to change logarithm equations to and from 
equivalent exponential equations:

 and  are equivalent.

Therefore your first equation:

 is equivalent to

 and then



Your second equation:



Using a rule of logarithms, becomes

, which is equivalent to

 and then



Substituting 4y-4 for x:









Substituting in 











Since logs cannot be taken of negative numbers, and
the original second equation contains  
and , the only solutions are the
positive ones:

 and 

Edwin

RELATED QUESTIONS

Log3(x+1)-log3(x)+log3(3) (answered by Alan3354)
Log3(x+1)=log3(x-1)+1 (answered by ikleyn,Alan3354)
log3(5x+5) - log3(x2 - 1) = 0 (answered by mukhopadhyay)
log3(2x-1) + log3(x-1)... (answered by josmiceli)
log3 5+log3 x=log3... (answered by scott8148)
log3 (x+2) + log3 (x-2) =... (answered by stanbon)
log3 (x+2) + log3(x-2) =... (answered by solver91311)
log3(x-1) - log3(x+2) =... (answered by edjones)
(log3(log3 x))=1 sove for... (answered by scott8148)