SOLUTION: 3log8x + 2log8x = 8
How do I solve?
Algebra.Com
Question 1100028: 3log8x + 2log8x = 8
How do I solve?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
first make it log (8x)^3+log (8x)^2=8
Then can make it log{(8x)^3*(8x)^2]=8, since the addition separately is multiplication under one log.
Then raise everything to the 10 power, and 10^8=100000000
8^5*x^5=10000000
divide by 8^5 to get 3051.76, don't round, then raise both sides to the (1/5) power
x=4.976
3 log (39.81, when not rounded)=4.8
2 log (39.81, when not rounded)=3.2
RELATED QUESTIONS
please solve given equation 3log(base8)x=-2 in other words 3log8x= -2..... just... (answered by lynnlo)
How do I solve s/3 =... (answered by tutorcecilia)
How do I solve... (answered by checkley71)
how do i solve... (answered by jojo14344)
How do i solve 13= 8-6r... (answered by checkley77)
how do i solve y=0-8 ?
(answered by nyc_function)
how do i solve log2... (answered by Alan3354,alegriajoy33)
how do i solve... (answered by Alan3354)
how do i solve 144 =... (answered by Alan3354)