SOLUTION: Can someone please help me with log base 3 of (n^2-3n+5)=2 ? Thank you!

Question 1098458: Can someone please help me with
log base 3 of (n^2-3n+5)=2 ?
Thank you!
Answer by ikleyn(52846) (Show Source): You can put this solution on YOUR website!
.

 = 2   <=== equivalently ===>

n^2 - 3n + 5 = 3^2 = 9  <=== equivalently ===>

n^2 - 3n - 4 = 0  =====>  factor left side  <=== equivalently ===>

(n-4)*(n+1) = 0  <=== equivalently ===>


The roots of the last equation are 4 and -1.


Check .  THERE IS NO NEED TO CHECK  since all transformations were equivalent (!).

Solved.

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