SOLUTION: #1) log4(x) + log4(x-3) = 1
This is what I've tried:
x(x-3) = 1
x^2 - 3x -1 = 0 ----> I can't factorise so do I need to complete the square to find x or is there an easier way o
Algebra.Com
Question 1095569: #1) log4(x) + log4(x-3) = 1
This is what I've tried:
x(x-3) = 1
x^2 - 3x -1 = 0 ----> I can't factorise so do I need to complete the square to find x or is there an easier way of doing it?
#2) log10(2x^2+3x+3) - log10(1-2x) = 1
I'm having the same factorising issue here.
Thankyou so much
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Is the base of log, 4 ?
, and you can take the rest from here.
You want the logarithms of non-negative numbers.
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