SOLUTION: Hi, I'm tried to solve these problems but I'm having trouble: 1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a

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Question 1095566: Hi, I'm tried to solve these problems but I'm having trouble:
1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a square root.
What I have tried: loga(x) + loga(x) - loga(square root y)
2) loge(x) - 3 = loge(square root x).....when x>0
Thankyou in advance.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
to help with question #1.
(In case the display does not work well, that is x to the one-half power.)
Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
Hi, I'm tried to solve these problems but I'm having trouble:
1) If loga(x) = 0.6 and loga(y) = 0.2, evaluate loga(x^2/square root y) - I don't know how to express loga(y) as a square root.
What I have tried: loga(x) + loga(x) - loga(square root y)
2) loge(x) - 3 = loge(square root x).....when x>0
Thankyou in advance.
1)               

     
     
      
     
      ------ Substituting  
     

2)  
     
     
     
      ----------- Converting to EXPONENTIAL form 
      ---- Squaring both sides

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