SOLUTION: Log2 (x+1) - Log2 X= Log2 4

Algebra.Com
Question 1094078: Log2 (x+1) - Log2 X= Log2 4
Answer by htmentor(1343)   (Show Source): You can put this solution on YOUR website!
Using the identity log(a) - log(b) = log(a/b), we have
log2((x+1)/x) = log2(4)
Eliminate the logarithm:
2^(log2((x+1)/x)) = (x+1)/x = 2^(log2(4)) = 2^2 = 4
Solve for x:
x+1 = 4x
x = 1/3

RELATED QUESTIONS

Log2 (x+1) - Log2 X= Log2 4 (answered by Gentle Phill)
log2(x+1) - log2(x-1) =... (answered by edjones)
log2(x)+log2(x+1)=log2(6) (answered by LinnW)
log2 (x+1) + log2 (x-5) =... (answered by solver91311)
log2^x+log2^4=3 (answered by edjones)
log2^(x+4)- log2^(x-4)=... (answered by Nate)
log2(x + 2) + log2(x - 4) =... (answered by lwsshak3)
log2(x + 1) + log2(x + 2) = log2... (answered by josmiceli)
log2(5-x)+log2(5+x)=4 (answered by Earlsdon)