SOLUTION: Hello, I'd like to know how to solve the following Logarithmic equation for x log<sub>125</sub>(1/5) = x I ended up doing this= 5·5^3x=5^1/

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Question 1090060: Hello, I'd like to know how to solve the following Logarithmic
equation for x
log125(1/5) = x


I ended up doing this= 5·5^3x=5^1/2
But it does not match with the solution I got on the calculator which is -6.
Thanks for your time.
Found 3 solutions by Edwin McCravy, Alan3354, MathTherapy:
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!


ANY logarithmic equation logB(A) = C
is equivalent to the exponential equation A = BC.

Therefore your logarithmic equation is equivalent to
the exponential equation 



Next we write 1/5 as 5-1 and 125 as (53)



We multiply the exponents on the right to remove the
parentheses:



Now Since the bases of the exponents on the laft and right are
equal, positive, and different from 1, the exponents must also
be equal, so we can drop the bases and set the exponents equal:



Divide both sides by 3



Edwin
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Makes no sense.
----------------
Logarithms are not solved, equations are solved.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Hello, I'd like to know how to solve the following Logarithm:
Log 125 (1:5)= X


I ended up doing this= 5·5^3x=5^1/2
But it does not match with the solution I got on the calculator which is -6.
Thanks for your time.
I don't know how you got what you got, but if it's , then:  

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