SOLUTION: solve the simultaneous equation (A) Logx=y=1/2log(2x-1) all log is in base 3 (B) logx=y=log(2x-1),the first log is in base 3 while the second log is in base 9
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Question 1086577
:
solve the simultaneous equation
(A) Logx=y=1/2log(2x-1) all log is in base 3
(B) logx=y=log(2x-1),the first log is in base 3 while the second log is in base 9
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MathLover1, MathTherapy
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Answer by
MathLover1(20850)
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Answer by
MathTherapy(10555)
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solve the simultaneous equation
(A) Logx=y=1/2log(2x-1) all log is in base 3
(B) logx=y=log(2x-1),the first log is in base 3 while the second log is in base 9
AMBIGUOUS!
If you need a correct answer (I would imagine you would), then fix and re-post!
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