SOLUTION: solve the equation log(x - 2^1/2) log(x 2^1/2) - log(x - 1) = 1 all log are in base 2

Algebra.Com
Question 1084694: solve the equation
log(x - 2^1/2) log(x 2^1/2) - log(x - 1) = 1
all log are in base 2

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
solve the equation
log(x - 2^1/2) log(x 2^1/2) - log(x - 1) = 1
all log are in base 2
=========================
Missing operator in the 2nd log, maybe others missing.

RELATED QUESTIONS

solve the equation. log(x+2)= -log(x-1)... (answered by Alan3354)
solve the equation log(5x-1) +... (answered by nerdybill,Fombitz)
Log(base 2) (x+1)-log(base 4)... (answered by lwsshak3)
Solve... (answered by MathLover1)
log base 2 (7x+1)=log base 2... (answered by jsmallt9)
log(x-1)+log(x+1)=Log(x+2)^2 (answered by stanbon)
log base 2 log(1-x)+log(5)=log(x^2-1) (answered by josgarithmetic)
Solve the equation {{{ log( 2x ) }}} = 1 + {{{ log(2) }}}... (answered by stanbon,MathTherapy)
log(x-1)+log(x+1)=2 (answered by vleith)