SOLUTION: b. log_6(x+4)+log

SOLUTION: b. log_6(x+4)+log_6(x-1)=1

Question 1076619: b. log_6(x+4)+log_6(x-1)=1
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log_6(x+4)+log_6(x-1)=1
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log6[(x+4)(x-1)] = 1
----
(x+4)(x-1) = 6
-----
x^2 + 3x -10 = 0
------
(x+5)(x-2) = 0
Positive solution::
x = 2
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Cheers,
Stan H.
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Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

.....since we have

.....if log same, than

....factor completely

solutions:
if =>
if =>......disregard negative solution
so, your solution is

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