SOLUTION: Log(3x+1)-log2=log11
Algebra.Com
Question 1075511: Log(3x+1)-log2=log11
Found 3 solutions by jorel1380, MathTherapy, josgarithmetic:
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
log(3x-1)-log 2=log 11
log(3x-1)/log 2=log 11
(3x-1)/2=11
3x-1=22
3x=23
x=23/3 ☺☺☺☺
Answer by MathTherapy(10556) (Show Source): You can put this solution on YOUR website!
Log(3x+1)-log2=log11
Correct answer:
Answer by josgarithmetic(39626) (Show Source): You can put this solution on YOUR website!
Log(3x+1)-log2=log11
RELATED QUESTIONS
Log(3x-1)-log2 equal to -3
(answered by Boreal)
solve for log(3x-1) + log2= log4 +... (answered by lwsshak3)
solve 2log3 +log2x = log(3x+1)
Evaluate 2logbase2 4 +3logbase2 5 -log-log2 25-log2... (answered by stanbon)
log... (answered by Fombitz)
log (x+20) - log2= log... (answered by MathLover1)
log2=log(6+4x)+log(3x+6) (answered by stanbon)
Express the following in index form
Logx + logy =1
Logx =6
Log (x+4) = log64
Log... (answered by stanbon)
log(5x+1)=log(2x+3)+log2 (answered by mananth)
Log X + log(6x+1)=log2
(answered by Boreal)