SOLUTION: Solving for x: logbase2(x+6)-logbase2(x-2)=3
Algebra
.Com
Question 1073513
:
Solving for x: logbase2(x+6)-logbase2(x-2)=3
Found 2 solutions by
josgarithmetic, ikleyn
:
Answer by
josgarithmetic(39618)
(
Show Source
): You can
put this solution on YOUR website!
use exponential form.
.
and
.
You should finish this.
Answer by
ikleyn(52792)
(
Show Source
): You can
put this solution on YOUR website!
.
--->
=
--->
=
---> x + 6 = 8*(x-2) ---> x + 6 = 8x - 16 ---> 7x = 22 ---> x =
.
RELATED QUESTIONS
Solve for x:...
(answered by
edjones
)
Solve for "x" logbase2 4 + logbase2 27= logbase2...
(answered by
Alan3354,nerdybill
)
solve logbase2(x+3)+...
(answered by
lwsshak3
)
SOLVE for x: a) logbase3 x + logbase3 (x-8)=2 b) logbase4 (x+2)+logbase4(x-4)=2 c)...
(answered by
edjones
)
Solve: a) logbase5 6-logbase5 x=logbase5 2 b) logbase2 8-logbase2 4=x c) logbase3 27+...
(answered by
stanbon
)
Logbase2 x =...
(answered by
Alan3354
)
Solve for x: x^2 - 5x = Logbase2...
(answered by
MathLover1
)
Please help me solve for x: a) logbase12(x^2-x)=1 b) (logbase2 x)^2-6*(logbase2 x)...
(answered by
edjones
)
A) if logbase4(xy)=6 then prove that logbase2(x) +logbase2(y) = 12 B) Hence solve the...
(answered by
josgarithmetic
)