SOLUTION: Logx-log16=log2x + logx
Solve for x
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Question 1070581: Logx-log16=log2x + logx
Solve for x
Found 2 solutions by josmiceli, Boreal:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Subtract from both sides
-------------------
check answer:
OK
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
that is log (x/16)= log (2x^2)
2x^2=x/16
x=1/32 ANSWER
log (1/32)-log 16=-2.709
log (1/512)=-2.709
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