SOLUTION: Solving for x when... 16^x = (1/2)^2*(8^(2x-1)) So far I've done... 16^x = (1/4)(8^(2x-1)) log(16^x) = log(2^(2x-1)) xlog(16) = (2x-1)*log(2) That's where I stopped.. This i

SOLUTION: Solving for x when... 16^x = (1/2)^2(8^(2x-1)) So far I've done... 16^x = (1/4)(8^(2x-1)) log(16^x) = log(2^(2x-1)) xlog(16) = (2x-1)log(2) That's where I stopped.. This i

Question 1065315: Solving for x when...
16^x = (1/2)^2*(8^(2x-1))
So far I've done...
16^x = (1/4)(8^(2x-1))
log(16^x) = log(2^(2x-1))
xlog(16) = (2x-1)*log(2)
That's where I stopped..
This is for a college population dynamics class -- we're doing algebra puzzles (for some reason).
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
HINT: Put everything into base-two.

The same base on both sides raised to the powers shown means the powers must be equal.

Continue to solve for x.
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