SOLUTION: Please help I'm having trouble trying to solve logarithm equation log(y+2)=1-log (2y-6)

Question 1064020: Please help I'm having trouble trying to solve logarithm equation log(y+2)=1-log (2y-6)
Answer by ikleyn(52908) (Show Source): You can put this solution on YOUR website!
.
Please help I'm having trouble trying to solve logarithm equation log(y+2)=1-log (2y-6)
~~~~~~~~~~~~~~~~~~~~~

log(y+2) = 1 - log (2y-6)   --->  log(y+2) + log (2y-6) = 1  --->  (y+2)*(2y-6) = 10.


Can you solve this quadratic equation ?


When you complete solution, check if the roots suit under logarithms.

RELATED QUESTIONS
Could you please help?! I'm trying to finish my online Algebra 2 class and the logarithm... (answered by dabanfield)

I am having trouble with this toic can someone please help me. Solve logarithmic... (answered by scott8148)

Please help me solve this equation. I am having trouble finding all the steps.... (answered by josgarithmetic,savvyhush23)

I'm about to go crazy over here trying to figure out this problem!!! Can you PLEASE tell... (answered by askmemath)

Write as a single logarithm a) 2 log 5 log b b) 3 log x + 1/2 log y c) 2 log m + log n (answered by lwsshak3)

Hi please help me with these three problems. I sure would appreciate your help.... (answered by stanbon,Nate)

please help! i"m trying to solve: (answered by Fombitz,ewatrrr)

Please help me solve this equation: Solve the logarithmic equation logarithmic... (answered by jim_thompson5910)

I need help in writing the expression as one logarithm: 2 log (Y^10/x) - 6 log y + 1/2 (answered by lwsshak3)