SOLUTION: log(3xto the power of 2+8)equals to 1+log(x\2+1)
Algebra.Com
Question 1063938: log(3xto the power of 2+8)equals to 1+log(x\2+1)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log(3xto the power of 2+8)equals to 1+log(x\2+1)
----
log(3x^2 + 8) = 1 + log((x/2)+1)
------
log[(3x^2 + 8)/((x/2)+1)] = 1
-------
(3x^2 + 8)/(x+2)/2 = 10
-------------------------
(3x^2+8) = 5x+10
-----
3x^2 - 5x - 2 = 0
(3x+1)(x-2) = 0
x = (1/3) or x = 2
--------------------
Cheers,
Stan H.
-----------
RELATED QUESTIONS
Please help me solve this equation:
Solve the logarithmic equation logarithmic... (answered by jim_thompson5910)
Log(4)x equals 1/2
(answered by josgarithmetic,MathTherapy,Alan3354)
how to solve 1/2 log base 3 of x equals to 2 log base 3 of... (answered by Alan3354)
Find the exact solution 8^(x-1)=16^(x+3)
I keep getting 3 log(2^x-1)=4 log(2^x+3)... (answered by stanbon,solver91311)
Please explain how to work this problem:
log of(x+1), base 2 plus 2 times the log... (answered by gonzo)
Simplify: log(x^3)- log(x^2) X^2 means X to the power of... (answered by user_dude2008,Alan3354)
log (x-4) = log 32 - log x
log (x+1) + 2*log (x) = log... (answered by josgarithmetic,MathTherapy)
I'm trying to get this expression down to a single logarithm.
1/4 log (x-2) - log(x) +... (answered by Alan3354)
log(3x^2+8)=1+log(x÷2+1) (answered by Edwin McCravy,MathTherapy)