SOLUTION: Please help me with this expression: logA/logB = A/B = 2/3. The correct answer is 2/3. It was solved correctly to = 2/3. The logs were canceled which is not a proper method of u

Question 106373: Please help me with this expression: logA/logB = A/B = 2/3. The correct answer is 2/3. It was solved correctly to = 2/3. The logs were canceled which is not a proper method of using logs. I need to know what A and B are so that logA/logB = 2/3.
I think the problem can be set up to look like: logA = log 2x and logB = log 3x. So, log2x/log3x = 2x/3x.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I need to know what A and B are so that logA/logB = 2/3.
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The "change of base rule" says logA/logB = log(baseB)A
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So your equation becomes
log(base B)A = 2/3
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Writing that in exponential form you get:
A = B(2/3)
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Therefore B = A(3/2)
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Cheers,
Stan H.
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