SOLUTION: log2x/ logx= 2 the correct working out to solve

Algebra.Com
Question 1062701: log2x/ logx= 2 the correct working out to solve
Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
.
log2x/ logx= 2 the correct working out to solve
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 =  2  --->

log(2x) = 2*log(x)  --->  log(2x) = log(x^2)  --->  2x = x^2  --->  x^2 - 2x = 0  --->  x(x-2) = 0  ---> 

the unique appropriate solution is x = 2.

(x = 0 doesn't work).

Answer. The solution is x = 2


RELATED QUESTIONS

Please help me solve log2x + logx =... (answered by stanbon)
Logx-log16=log2x + logx Solve for x (answered by josmiceli,Boreal)
logx to the base2=log2x+10 to the base root2 (answered by lwsshak3)
(log2x+logx)/(log2x-logx)=3 (answered by Alan3354,nerdybill)
(logx/log2x)=(log4x/log8x) solve for... (answered by stanbon)
solve for x: log2x^3 - logx = log16 - logx (answered by jsmallt9)
Please help me solve this problem: log16x+log4x+log2x=7. I know you have to use the... (answered by lwsshak3)
rounded to the nearest tenth, algebraically find the solution(s) of... (answered by nerdybill)
Log2x+logx=11 (answered by Fombitz)