SOLUTION: log4(1/8)+log8(1/4)-log2(64)

Algebra.Com
Question 1062533: log4(1/8)+log8(1/4)-log2(64)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Assuming the three different bases are being attempted expressed,





------Change Of Base formula












---
,

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
log4(1/8)+log8(1/4)-log2(64)
Correct answer: 


Student's response
====================================================== TEXT FOLLOWS
please can I see your workings
====================================================== END TEXT


, in EXPONENTIAL form is:
, in EXPONENTIAL form is:
, in EXPONENTIAL form is:
This gives us:
You could have also kept it in logs and gotten the same answer.
RELATED QUESTIONS

log2(64)... (answered by Alan3354)
Simplify log8+log4-log2 (answered by fractalier,Alan3354)
please help, it my homework. log5to power 125 + log4(1/16)+log2 to power 32 -log8 to... (answered by lwsshak3)
prove that : {{{25^(log8)*8^(log4)}}}{{{""=""}}}{{{64}}} (answered by Edwin McCravy)
evaluate e^2ln3 (2^3*2^-5)/2^-7 log4 64 log4 32 log2 4th... (answered by stanbon)
Log2^x log4^x... (answered by MathLover1)
Log2^x+log4^x+log8^x=21/4, find... (answered by lwsshak3)
log8 1/64... (answered by robertb)
Express as a difference of logarithms. log4 1 - log4 2 log8 1... (answered by solver91311)