SOLUTION: Solve for x: 9^(2x-1)=(1/3)^x

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Question 1056039: Solve for x: 9^(2x-1)=(1/3)^x
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Solve for x: 9^(2x-1)=(1/3)^x
----------
(2x-1)*log(9) = x*log(1/3)
2x*log(9) - log(9) = x*log(1/3)
2x*log(9) - x*log(1/3) = log(9)
x*log(81) - x*log(1/3) = log(9)
x*(log(81) - log(1/3)) = log(9)
x*log(243) = log(9)
x = log(9)/log(243) = 2log(3)/(5log(3))
x = 2/5

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Solve for x: 9^(2x-1)=(1/3)^x


 ----- Converting 





4x – 2 = - x ------ Bases of equation are equal and so are the exponents

4x + x = 2

5x = 2

 

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