SOLUTION: I need someone's help. I need to find the value of x from logx169/121= 2?? Can someone please help me out on this?? Thank You!

Question 105570This question is from textbook Intermediate Algebra
: I need someone's help. I need to find the value of x from logx169/121= 2??
Can someone please help me out on this?? Thank You! This question is from textbook Intermediate Algebra

Found 2 solutions by bucky, ankor@dixie-net.com:
Answer by bucky(2189) (Show Source): You can put this solution on YOUR website!
You are given the equation:
.

.
To solve for x you can convert the given logarithmic equation to its equivalent exponential
form using the following translation format:
.
is equivalent to the exponential form
.
Note that by comparing the given equation to the translation format you can see from the
positions in the equations that:
.
,
and

.
Substituting values for b, A, and y into the exponential form results in:
.

.
You can then solve for x by taking the square root of both sides to get:
.

.
So the answer to your problem is
.
It's a good idea to become very familiar with switching back and forth between the logarithmic
and exponential forms. This switching is often used in solving logarithmic equations.
.
Hope this helps you to understand this problem.

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
find the value of x from log x(169/121) = 2
:
Assume you mean log to the base x:
= 2
Write the equation in it's equivalent exponential form:
=
:
Same as:
x =
:
Both 169 and 121 are perfect squares:
x =
:
Study the "properties of exponents" in the logarithm section of your book and it will make sense to you. A
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