SOLUTION: If x=log10^12,y=log4^2Ślog10^9 and z=log10^0.4 find x-y-z

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Question 1052802: If x=log10^12,y=log4^2Ślog10^9 and z=log10^0.4 find x-y-z
Answer by Edwin McCravy(20059)   (Show Source): You can put this solution on YOUR website!

log(A) means the power to which 10 must be raised to give A.

log10^12 = 12 because the power to which 10 must be raised
in order to get 10 raised to the 12th power is 12.

log10^9 = 9 because the power to which 10 must be raised
in order to get 10 raised to the 9th power is 9.

log10^0.4 = 0.4 because the power to which 10 must be raised
in order to get 10 raised to the 0.4th power is 0.4.

[The above requires the same reasoning as 

"The city to which you must be in -- 
in order to be in Chicago -- is Chicago."  :)]

So

If x=log10^12,y=log4^2Ślog10^9 and z=log10^0.4 find x-y-z

becomes:

If x=12,y=log4^2Ś9 and z=0.4 find x-y-z

So x-y-z = 12-9Ślog4^2-0.4 = 11.6-9Ślog4^2 = ll.6-9Ślog16 = 

11.6-9Ś1.204119983 = 0.762920153.

Edwin

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