SOLUTION: Please tell me how I need to approach this,I'm so stuck!!
Solve the following system of equations:
log(x+1)^y=2
log(y+1)^x=1/4
Thank you!!
Algebra.Com
Question 1051646: Please tell me how I need to approach this,I'm so stuck!!
Solve the following system of equations:
log(x+1)^y=2
log(y+1)^x=1/4
Thank you!!
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Use the log properties,
.
.
.
RELATED QUESTIONS
Please help,I'm so stuck:
Solve the system of equations
log(x+1)y=2
log(y+1)x=1/4
(answered by Alan3354)
How do I approach, and solve, this problem?:
2^logX + 3^logY = 2^log(X+1) + 3^log(Y+1)
(answered by arunpaul)
Hi, I need help in solving this logarith problem:-
Solve the simultaneous equations
(answered by Earlsdon)
I need help. I am stuck on this one. How do I graph the following:
y=(2^x+1)+3 and... (answered by Fombitz)
Can you help me please?
I can't post the graph but I can tell you the equation which is... (answered by Alan3354)
D1: Let’s combine our knowledge of solving systems and solving logarithmic equations.... (answered by josgarithmetic,MathLover1)
(1/3)log[2]x = -3
I need to know x.
I tried the following:
(1/3)log[2] x = log... (answered by Alan3354)
y=log(x)
y=x^0.3
please help me solve this system of equations
(answered by stanbon)
i am stuck in graphs of linear equations.could you please tell me how to solve the... (answered by Alan3354)