SOLUTION: If x=log15 2, y= log10 3, z=log6 5; prove that xy + yz + zx + 2xyz = 1

Algebra.Com
Question 1045915: If x=log15 2, y= log10 3, z=log6 5; prove that xy + yz + zx + 2xyz = 1
Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
.
Similarly, , and
.
===>
= .

Also,


=

===>

=
=
=
=

RELATED QUESTIONS

SOLUTION: If x=log15 2, y= log10 3, z=log6 5; prove that xy + yz + zx + 2xyz =... (answered by ikleyn)
prove that for x,y,z>=0,... (answered by robertb)
Hi, If x= log of 2 to the base 15; y= log of 3 to the base 10 and z=log of 5 to the... (answered by lwsshak3)
x^2+y^2+z^2- xy -yz-zx-yz=0 then prove that x=y=z (answered by Edwin McCravy)
If x = 1+ log a bc, y=1+log b ca and z=1+log c ab, prove that xyz =... (answered by tanimachatterjee)
x^2+xy+yz+zx=30 y^2+xy+yz+zx=15 z^2+xy+yz+zx=18 find... (answered by richwmiller,ikleyn)
If x+y+z=5 and xy+yz+zx=3,then least and largest value of x are... (answered by karaoz)
Please help me solve these equations 1) x + y + z = 3 x + 2y - z = 2 x + yz + zx = 3 (answered by Alan3354,ikleyn,MathTherapy)
x= 1+log[base a]bc , y= 1+log[base b]ca , z= 1+log[base c]ab. Then PROVE THAT :... (answered by anand429)