SOLUTION: a^2+b^2=7ab.prove 2 log (a-b)=log 5+log a +log b.

SOLUTION: a^2+b^2=7ab.prove 2 log (a-b)=log 5+log a +log b.

Algebra.Com

Question 1043552: a^2+b^2=7ab.prove 2 log (a-b)=log 5+log a +log b.
Answer by ikleyn(52815) (Show Source): You can put this solution on YOUR website!
.
Just solved in
https://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.1043490.html

https://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.1043490.html

RELATED QUESTIONS
If a^2+b^2=7ab prove that 2 log(a-b)=log 5+log a+log... (answered by ikleyn)

if a^2+b^2=7ab,prove that log 1/3(a+b)=1/2[log a+log... (answered by CharlesG2)

If a^2+b^2=7ab,prove that log{1/3(a+b)}=1/2(log a + log b) (answered by ikleyn)

5 (log A + log B) - 2 log... (answered by user_dude2008,stanbon)

If a^2+b^2=7ab how to prove log(a+b)/3=1/2(log a+log b) thank... (answered by mananth)

2(Log a + Log b) � Log a � 2Log... (answered by Alan3354,josgarithmetic)

log 24 use log 2=a and log... (answered by richard1234)

If a^2 + b^2=5 ab.prove that 2 log (a+b)=log 7+log a+log... (answered by Boreal,ikleyn)

If a^2 + b^2 =14ab, prove that log ((a+b)/4) = 1/2 (log a+log b... (answered by mananth)