SOLUTION: hi tutors..thanks for all your help.How do I solve log base of 125^1/5
(5^3)^x=1/5
5^3x=1/5
then i used base 5 to each side
logbase5(5^3x+log base5(1/5)
then i did 3x=1
then
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Question 1043528: hi tutors..thanks for all your help.How do I solve log base of 125^1/5
(5^3)^x=1/5
5^3x=1/5
then i used base 5 to each side
logbase5(5^3x+log base5(1/5)
then i did 3x=1
then x=1/3
but my book says -1/3
can i have a detail account where i got this wrong
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
solve log base of 125^1/5
= y
exponent equiv
=
1/5 can be written as
=
125 is five cubed
=
therefore
3y = -1
y =
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