SOLUTION: How do I express this as a single logarithm? log5+ 2log2+log3-log6

Question 1042383: How do I express this as a single logarithm?
log5+ 2log2+log3-log6
Found 2 solutions by Alan3354, jim_thompson5910:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How do I express this as a single logarithm?
log5+ 2log2+log3-log6
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Adding logs --> multiply
Subtracting logs ---> division.
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Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'm assuming these logs are all base 10.

We'll use the following rules:

Rule 1:

Rule 2:

Rule 3:

Rule 4: where b is not equal to 1 and b > 0. In this case, I'm assuming the value of b is 10.

-------------------------------------------------

Use Rule 3

Use Rule 1

Use Rule 1

Use Rule 2

Use Rule 4

-------------------------------------------------

So simplifies to

In other words,
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