SOLUTION: 2log( x ) = log(2) + log(5x-8)
{{{log( x )^2 = log(2) + log(5x-8)}}}
{{{log( x )^2 = log(2)(5x-8)}}}
you can write
{{{( x )^2 = (2)(5x-8)}}}
{{{( x )^2 = 10x-16}}}
{{{( x )
Algebra.Com
Question 104232: 2log( x ) = log(2) + log(5x-8)
you can write
x1=
=
=
x2=
=
=
SO THERE ARE TWO SOLUTION
8 AND 2
Found 2 solutions by scott8148, bimanewton:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
using rules for logarithms; x^2=2(5x-8)
x^2=10x-16 ... x^2-10x+16=0 ... (x-8)(x-2)=0
Answer by bimanewton(8) (Show Source): You can put this solution on YOUR website!
you can write
x1=
=
=
x2=
=
=
SO THERE ARE TWO SOLUTION
8 AND 2
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