SOLUTION: -1+10log2(4t+5)=19
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Question 1039383: -1+10log2(4t+5)=19
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
divide both sides by 10
The exponent equiv of logs
(4t+5) = 2^2
4t + 5 = 4
4t = 4 - 5
4t = -1
t = -1/4
:
:
Check solution in the original equation
log base 2 of 4 is 2, therefore
-1 + 10(2) = 19
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