SOLUTION: If y = log2( x + sqrt(x^+1) ), then 2^y - 2^-y = _______ x
Algebra.Com
Question 1037480: If y = log2( x + sqrt(x^+1) ), then 2^y - 2^-y = _______ x
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
==> .
Also, .
==>
=
= .
The answer is now obvious.
RELATED QUESTIONS
if log2 x=5+log2 y,then... (answered by josmiceli)
If {{{x}}}{{{""=""}}}{{{y + sqrt(y^2+1)}}}, then express y in terms of x
(answered by Edwin McCravy)
solve the simultaneous equation:
1.) log2^x - log2^y =2, log2^(x-2y) =3 (answered by Alex.33,MathTherapy)
If 1= 2(x+y), then... (answered by Fombitz)
If x = sqrt 3 + sqrt 2 over sqrt 3 - sqrt 2 and y=1, then the value of x-y over
x-3y is (answered by Edwin McCravy)
If x^2+y^2=146xy then show that... (answered by math_tutor2020,ikleyn)
y = sqrt(x+1)^2 -... (answered by checkley71)
Find the x & y intercept
y-2=log2(x+3)
(answered by stanbon)
log(x-y)-log2=logx+log(x-y^2) (answered by Alan3354)