SOLUTION: ln(x^2+3x-4)-ln(x+14)=3

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Question 1034961: ln(x^2+3x-4)-ln(x+14)=3
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
ln(x^2+3x-4)-ln(x+14)=3
ln(x^2+3x-4) = ln(x+14) + 3 = ln(x+14) + ln(e^3)
ln(x^2+3x-4) = ln(e^3*(x+14))
x^2+3x-4 = e^3*(x+14) = e^3x + 14e^3
x^2 + (3-e^3)x - (4+14e^3) = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1432.70557195361 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 27.4683171455397, -10.3827802223519. Here's your graph:


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