SOLUTION: Solve the equation 3x^3 +19x^2 +13x-35=0 given that -7/3 is a zero of f(X) = 3x^3+19^2+13x-35 Use synthetic division and find the zeros

Question 1032219: Solve the equation 3x^3 +19x^2 +13x-35=0 given that -7/3 is a zero of f(X) = 3x^3+19^2+13x-35
Use synthetic division and find the zeros
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve the equation 3x^3 +19x^2 +13x-35=0 given that -7/3 is a zero of f(X) = 3x^3+19^2+13x-35
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-7/3).....3.....19.....13.....-35
..........3.....12....-15....|..0
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Quotient:: 3x^2 + 12x - 15
Solve 3x^2 + 12x - 15 = 0
x^2 + 4x - 5 = 0
Factor::
(x+5)(x-1) = 0
x = -5 or x = 1
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Cheers,
Stan H.
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