when you have an equation where x is in the log function and x is in the exponent, i haven't been able to figure out how to solve that type of equation without resorting to graphing.
by graphing, i got the following:
x1 is equal to -.6318474
x2 is equal to .66846195
both x1 and x2 are solutions to the equations.
i confirmed by replacing x with the value of x1 in the original equation, and by replacing x with the value of x2 in the original equation.
both values are confirmed to be solutions because the original equation is true after evaluating the original equation with those respective values of x.
i graphed y = log(x^16) - log(2^x) and i graphed y = -3.
the intersection of those two equations on the graph are the solutions.
the graph of my equation is shown below.
the solutions shown there are rounded.
i also graphed on my TI-86 plus.
those solutions were still rounded, but allowed for more decimal digits to be displayed.
